In an ap the sum of the first 10 terms
WebAnswer: Let a be the first term and d be the common difference. 14th term = a + 13d = 100 27th term = a + 26d Sum of n terms = n/2 (2a+ (n-1)d) Sum of first 27 terms = (27/2)(2a+26d) Sum of first 27 terms = (27/2)(2)(a+13d) = 27(a+13d) = 27(100) [(a+13d)=100] = 2700 WebApr 4, 2024 · Hint: Assume that the first term of the AP is ‘a’ and the common difference is ‘d’. Write the last term of the AP using the formula a n = a + ( n − 1) d for writing the n t h …
In an ap the sum of the first 10 terms
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WebClass 10 math (India) > Arithmetic progressions > Sum of first n terms of an AP Finding first term and common difference when sum is given Google Classroom In an arithmetic sequence: S_ {20} = 500 S 20 = 500 a_ {20}= 44 a20 = 44 Find the first term, a_1 a1, of the … WebQuestion: in an AP of 50 terms ,the sum of first 10 terms is 210 and the sum of its last 15 terms is 2565 find the AP. in an AP of 50 terms ,the sum of first 10 terms is 210 and the …
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WebThis is the formula to find the sum of the first n n terms of the geometric sequence. To evaluate it, find the values of r r and a1 a 1. Sn = a1(rn − 1) r−1 S n = a 1 ( r n - 1) r - 1. … WebWe know the general form of GP for first five terms is given by: a, ar, ar 2, ar 3, ar 4 a = 10 ar = 10 × 3 = 30 ar 2 = 10 × 3 2 = 10 × 9 = 90 ar 3 = 10 × 3 3 = 270 ar 4 = 10 × 3 4 = 810 Therefore, the first five terms of GP with 10 as the first term and 3 as the common ratio are: 10, 30, 90, 270 and 810
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